An woman walks on a straight road from her home to a market 2.5 km away with a speed of 5 km/h . Finding the market closed .he instantly turns and walks back with a speed of 7.5 km/hr. What is the(a)magnitude of an average velocity ,(b)average speed of the man,over the interval of time .0 to 50 min and

An woman walks on a straight road from her home to a market 2.5 km awa

1.	An woman walks on a straight road from her home to a market 2.5 km away with a speed of 5 km/h . Finding the market closed .he instantly turns and walks back with a speed of 7.5 km/hr. What is the(a)magnitude of an average velocity ,(b)average speed of the man,over the interval of time .0 to 50 min and
Answer» SOLUTION :TIME taken by woman to go from her home to market `t_(1) =("Distance") /("Speed") = (2.5)/(5) = (1)/(2)` h Time taken by woman to go from market to her home, `t_(2) = (2.5)/(7 . 5) = (1)/(3) h` `:.`TOTAL time`= t_(1) + t_(2) = (1)/(2) +(1)/(3) = (5)/(6)`h =50 min (a)Average velocity `vec(v) _(av) = ("Displacement")/("Time")` (b)Average sped `v_(av) = ("Distance")/("Time")` Between 0 to 50 min ` {:("Total distance"),("travelled"):}}= 2 . 5 + 2 . 5 = 5 km ` `{:("Total"),("displacement"):}}= zero` `vec(v)_(av) = 0` `v_(av) = (5)/((5)/(6))= 6 `km /hr