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Analyses shows that FeO has a non-stoichiometric composition with formula `Fe_(0.95)O_(1.00)`. Give reason.

Answer» In FeO , some `Fe^(2+)` ions are replaced by `Fe^(3)` ions i.e., `3Fe^(2+) -= 2 Fe^(3+)` to maintain electrical neutrality. Hence , due to metal deficiency , the compounds obtained are non-stoichiometric composition with formula `Fe_(0.95)O`.


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