1.

Analysis shows that nickel oxide has the formula `Ni_(0.98)O_(1.00)`. What fractions of nickel "exist" as `Ni^(2+)` and `Ni^(3+)` ions?

Answer» `Ni_(0.98)O_(1.00)`
Let `Ni^(2+)` be `a` and `Ni^(3+)` be `(1-a)` , then average oxidation no. of `Ni`.
`axx2+(1-a)xx3=(2xx100)/(0.98)`
`:. a=0.959`
`:. Ni^(2+)=0.959,Ni^(3+)=0.041`
The percentage of `Ni^(2+)` is `95.9%~~96%` and that of `Ni^(3+)=4%`


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