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and R are three collinear points. P and Q are (3,4) and (7, 7) respectively, and, 10 units. Find the coordinates of R. |
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Answer» Given P=(3,4) and Q=(7,7)PQ=√(3-7)^2+(4-7)^2=√16+9=√25=5But PR=10unitsQR=5unitsSo Q is mid point of PRLet (X,y) be coordinates of RSince Q is midpoint of PR3+X/2=7x=114+y/2=7y=10Coordinates are (11,10) |
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