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And the pointaonline ?32-yt,z-3 at a distance ofsunits Poom the poin t P(1,3,3)2

Answer»

(x+2)/3 = (y+1)/2 = (z-3)/2=k(let)

(x+2)/3=k and (y+1)/2=k and (z-3)/2=k

given x=3k-2,y=2k-1,z=2k+3 given(x,y,z) is at a distance of 5 from(1,3,3)

sqrt[(3k - 3)^2+(2k - 4)^2+(2k)^2] = 5

squaring on both sides

9k^2 + 9 - 18k + 4k^2 + 16 - 16k+ 4k^2 = 2517k^2 - 34k = 0k(17k - 34) = 0

k=0 or k=2

substitute k=0 x=1, y=1, z=5 therefore point is (1, 1, 5)



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