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And the pointaonline ?32-yt,z-3 at a distance ofsunits Poom the poin t P(1,3,3)2 |
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Answer» (x+2)/3 = (y+1)/2 = (z-3)/2=k(let) (x+2)/3=k and (y+1)/2=k and (z-3)/2=k given x=3k-2,y=2k-1,z=2k+3 given(x,y,z) is at a distance of 5 from(1,3,3) sqrt[(3k - 3)^2+(2k - 4)^2+(2k)^2] = 5 squaring on both sides 9k^2 + 9 - 18k + 4k^2 + 16 - 16k+ 4k^2 = 2517k^2 - 34k = 0k(17k - 34) = 0 k=0 or k=2 substitute k=0 x=1, y=1, z=5 therefore point is (1, 1, 5) |
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