Andy has twice as many marbles as Pandy, and Sandy has half as many ha

1.	Andy has twice as many marbles as Pandy, and Sandy has half as many has Andy and Pandy put together. If Andy has 75 marbles more than Sandy. How many does each of them have?
Answer» Let the number of marbles with Pandy = x So, the number of marbles with Andy = 2x Thus, the number of marbles with Sandy = (x/2) + (2x/2) = (3x/2) According to the question: ⇒ 2x + 75 = (3x/2) By transposing we get ⇒2x – (3x/2) = -75 ⇒ (4x – 3x)/2 = -75 ⇒ (x/2) = -75 ⇒ x = -150 Since number of marbles cannot be negative Therefore x = 150 So, Pandy has 150 marbles, Andy has 2x = 2 (150) = 300 marbles, Sandy has 3x/2 = 225 marbles.

Andy has twice as many marbles as Pandy, and Sandy has half as many has Andy and Pandy put together. If Andy has 75 marbles more than Sandy. How many does each of them have?

Answer»

Let the number of marbles with Pandy = x

So, the number of marbles with Andy = 2x

Thus, the number of marbles with Sandy = (x/2) + (2x/2) = (3x/2)

According to the question:

⇒ 2x + 75 = (3x/2)

By transposing we get

⇒2x – (3x/2) = -75

⇒ (4x – 3x)/2 = -75

⇒ (x/2) = -75

⇒ x = -150

Since number of marbles cannot be negative

Therefore x = 150

So, Pandy has 150 marbles,

Andy has 2x = 2 (150) = 300 marbles,

Sandy has 3x/2 = 225 marbles.