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Ange įr divided at DLe.th0壍BD%BC..2. |
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Answer» GIVEN:BD = 1/2 DCCONST:Draw a line ⊥ BC, AE⊥ BCLet AE = h (Ht. ofΔABC)∵ BD + DC = BCBD + 2BD = BC3BD = BCBD = 1/3 BCAr.ΔABD = 12× BD× AE = 1/2× (1/3 BC)× AE= 13× 12 = BC× AE= 13× Ar. ABC |
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