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Angle ABC = 50∘ and BA = BC = 5 cm. The mid points of BA and BC are M and N respectively. Draw the locus of a point which is equidistant from BA and BC, 2.5 cm from M and 2.5 cm from N. Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Then the length of PC is |
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Answer» Angle ABC = 50∘ and BA = BC = 5 cm. The mid points of BA and BC are M and N respectively. Draw the locus of a point which is equidistant from BA and BC, 2.5 cm from M and 2.5 cm from N. Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Then the length of PC is |
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