1.

Angle between the planes 2x+2y−3z−5=0 and 3x−3y+5z−3=0 is cos−1k√17√43 then k is

Answer» Angle between the planes 2x+2y−3z−5=0 and 3x−3y+5z−3=0 is cos−1k√17√43 then k is


Discussion

No Comment Found