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Angle of deviation in cyclo butane is???? |
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Answer» The bond angle in CYCLOBUTANE is 90˚. The NORMAL tetrahedral bond angle value is 109.5˚. That is why, deviation = (normal tetrahedral bond angle) – (actual bond angle) • Deviation = 109˚ 5' – 90 = 19.5˚. Deviation for CYCLOPROPANE is 49.5˚ • Deviation for cyclobutane is 19.5˚.. I HOPE it will help you. Plzz mark my ANSWER as brainlist. Plzz follow me freind |
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