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Angles of a quadrilateral are (4x), 5(x+2), (7x-20) and 6(x+3). Find the value of x and each angle of the quadrilateral |
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Answer» Angles of quadrilateral are, (4x)°, 5(x+2)°, (7x – 20)° and 6(x+3)° ∴ 4x + 5(x + 2) + (7x - 20) + 6(x + 3) = 360° 4x + 5x + 10 + 7x - 20 + 6x + 18 = 360° 22x + 8 = 360° 22x = 360° - 8° 22x = 352° x = 16° Hence angles are, (4x)° = (4 × 16)° = 64° 5(x + 2)° = 5(16 + 2)° = 90° (7x - 20)° = (7 × 16 - 20)° = 92° 6(x + 3)° = 6(16 + 3) = 114° |
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