Angular velocity of a body moving on a circular track is given by →ω=^i+^j+^k and the radius vector →r=2^i−2^j−2^k at the instant of time ‘t′. Then the magnitude of linear velocity of the body at that instant is.

Angular velocity of a body moving on a circular track is given by →�

1.	Angular velocity of a body moving on a circular track is given by →ω=^i+^j+^k and the radius vector →r=2^i−2^j−2^k at the instant of time ‘t′. Then the magnitude of linear velocity of the body at that instant is.
Answer» Angular velocity of a body moving on a circular track is given by $\to ω =^i +^j +^k$ and the radius vector $\to r = 2^i - 2^j - 2^k$ at the instant of time $‘ t^{'}$ . Then the magnitude of linear velocity of the body at that instant is.

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Angular velocity of a body moving on a circular track is given by →ω=^i+^j+^k and the radius vector →r=2^i−2^j−2^k at the instant of time ‘t′. Then the magnitude of linear velocity of the body at that instant is.

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