Ans. Refer Solved Example 3 (Page 991).0.2. Why is sulphurie acid not

1.	Ans. Refer Solved Example 3 (Page 991).0.2. Why is sulphurie acid not used during the reaction of alcohols with KI ?during the reaction to I
Answer» In the presence of sulphuric acid (H2SO4), KI produces HI 2KI + H2SO4→ 2KHSO4 + 2HI Since H2SO4is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). 2HI + H2SO4 → I2 + SO2 + H2O As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4is used.

Ans. Refer Solved Example 3 (Page 991).0.2. Why is sulphurie acid not used during the reaction of alcohols with KI ?during the reaction to I

Answer»

In the presence of sulphuric acid (H2SO4), KI produces HI

2KI + H2SO4→ 2KHSO4 + 2HI

Since H2SO4is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).

2HI + H2SO4 → I2 + SO2 + H2O

As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4is used.

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Ans. Refer Solved Example 3 (Page 991).0.2. Why is sulphurie acid not used during the reaction of alcohols with KI ?during the reaction to I

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