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Ansteeslook 150 Woses onlyA ball is thrown vertically up words and sisto a heightof 126.5 m. calculate thei velocity by which the ball was thrown upwards and2the time taken by the ball to reach the highest point.(Given is g = 985 )​

Answer» <html><body><p><strong>Answer:</strong></p><p>Given the height at which ball is <a href="https://interviewquestions.tuteehub.com/tag/thrown-7258593" style="font-weight:bold;" target="_blank" title="Click to know more about THROWN">THROWN</a>, h = 126.5 m.</p><p></p><p>1) To calculate the initial velocity of ball by which ball was thrown, use equation of motion,</p><p><a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> ^2 - u ^2 = 2 gh</p><p></p><p>Here, u is the initial velocity v is final velocity and h is height at which ball reached.</p><p></p><p>At height 126.5 m (maximum height) , the final velocity is zero.</p><p></p><p>Substitute the given values, we get</p><p>0= u ^2 - 2× 9.8m/sec ^2 × 126.5m</p><p>u = √2× 9.8 m/ sec ^2 × 126.5 </p><p>u = 49.79m / sec </p><p></p><p>Thus, the velocity by which the ball was thrown is 49.79 m/s.</p><p></p><p>2) To calculate the time taken by the ball to reach the <a href="https://interviewquestions.tuteehub.com/tag/highest-1022683" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHEST">HIGHEST</a> point, use equation of motion</p><p></p><p>v = u - gt</p><p>Substitute the values, we get</p><p>0 = 49.79 - 9.8 m/ sec ^2 ×t </p><p>t = 49 .79 m/ sec ÷ 9.8 m/ sec </p><p>t = 5 .08 sec </p></body></html>


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