Answer any FOUR of the following questions. b. How do you prepare methoxy ethane by Williamson's ether synthesis?

Answer any FOUR of the following questions. b. How do you prepare met

1.	Answer any FOUR of the following questions. b. How do you prepare methoxy ethane by Williamson's ether synthesis?
Answer» SOLUTION :(a) Step 1 : FORMATION of proptonated alcohol. Step 2 : Formation of carboncation : `H-UNDERSET(H)underset(\|)overset(H)overset(\|)(C )-underset(H)underset(\|)overset(H)overset(\|)(C )-overset(H)overset(\|)(underset(ddot)O)-Hoverset("Slow")( Step 3: Elimination of proton - (b) When sodium sodium ethoxide is heated with methyl iodide (in alcoholic medium), methoxyethane is formed `underset("Sodium ethoxide")(CH_3CH_2)-ONa) + underset("Methoxy iodine")(I-CH_3) underset(Delta)overset("Alcohol")(rarr)underset("Methoxy methane")(CH_3CH_2-O-CH_3+NaI)` DETAILED ANSWER: (b) In a Williamson synthesis, an ether is formed by reacting an alcohol and an alkyl halide in the presence of a base. When `CH_3-I` is mixed with the base, like `NaOH`, the alcohol is deprotonated, leaving a negatively charged oxygen. This acts as a nucleophile and attacks the carbon bonded to the halogen(iodide). The halogen, a good leaving group, is released, leaving behind methoxy ethane.