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Answer both of the following questions: (a) The four angles of a quadrilateral areas 2:4:1:5. Find the angles.(b) Is an equilateral triangle a regularpolygon? |
Answer» <html><body><p>Consider the angles of a quadrilateral as <a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a>, 4x, 5x and 7x In a quadrilateral we <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that the sum of all the angles is 360o So we can write it as 2x + 4x + 5x + 7x = 360o By addition <a href="https://interviewquestions.tuteehub.com/tag/18x-280580" style="font-weight:bold;" target="_blank" title="Click to know more about 18X">18X</a> = 360o By division <a href="https://interviewquestions.tuteehub.com/tag/xo-748060" style="font-weight:bold;" target="_blank" title="Click to know more about XO">XO</a> = 20o Now by substituting the value of xo 2x = 2(20o) = 40o 4x = 4(20o) = 80o 5x = 5(20o) = 100o 7x = 7(20o) = <a href="https://interviewquestions.tuteehub.com/tag/140o-273545" style="font-weight:bold;" target="_blank" title="Click to know more about 140O">140O</a> Therefore, the angles are 40o, 80o, 100o and 140o.Step-by-step explanation:Nikuuu~</p></body></html> | |