Answer questions on the basis of your understanding of the followingparagraph and the related studied concept. Electric flux, in general , through any surface is defined as per relation: phi_E= int oversetto E. oversetto (ds), whereintegration has to be performed over the entire surface through which flux is required. The surface under consideration may be a closed one or an open surface. Whenflux through a closed surface is required we use a small circular sign on the integrationsymbol. Thus flux over a closed surface oint E= oint oversetto E. oversetto (ds) .it is customary to take the outward normal as positive in this case. A German physicist Gauss established a fundamental law to find electric flux over a closed surface. As per Gauss' law , the flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by in_0 . Mathematically oint oversetto (E) . oversetto (ds) =(1)/( in_0)[q_(en) ], where q_(cn)is the net charge enclosedwithin the surface. It is possible to derive Gauss' lawfrom Coulomb's laws. Gauss' lawcan be applied to obtain electric field at a point due to continuous charge distribution for a number of symmetric charge configurations. A square surface of side L m is in the plane ofpaper. A uniform electric fieldoversetto EV m ^(-1), also in the plane of the paper, is limited only to the lower half of the square surface as shown in adjoining figure. The electric flux, in SI units, associated with the surfer is : (##U_LIK_SP_PHY_XII_C01_E03_012_Q01.png" width="80%">