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Answer» ka ❤ Given, ✴distance from the closest wall = 660✴time taken to hear FIRST echo = 4s✴ time taken to hear second echo = 2sCASE IWe know that, So, Hence, the velocity of sound is 330m/s.CASE IILet the distance be x from the second wall.So, echo = 2x ÷ (time taken)Time taken = 4s + 2s = 6sNow, finding x => x = echo × time ÷ 2=> x = 330 × 6 ÷ 2=> x = 1980 ÷ 2=> x = 990mHence, the distance from second wall is 990m .DISTANCE B/W TWO WALLS = 990 + 660= 1650 m HOPE it HELPS ✔ |
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