Answer the following: (which help you understand the difference between Thomson's model and Rhutherford's model better). (a) Is the average angle of deflection of alpha particles by a thin gold ofil predicted by Thomson's model much less, about the same or much greater than that predicted by Rutherford's atom model? (b) Is the probability of backward scattering (i.e., scattering of alpha particles at angles greater than 90^(@)) predicted by Thomson's model, much less, about the same, or much greater than that predicted by Rutherford's model? (c) Keeping other factors fixed, it is found experimentally,that for a small thickness t, the number of alpha particles scattered at moderate angles is propotional to t. What clues does this linear dependence on t provide? (d) In which atom model, is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of alpha particles by a thin ofil?

Answer the following: (which help you understand the difference betwe

1.	Answer the following: (which help you understand the difference between Thomson's model and Rhutherford's model better). (a) Is the average angle of deflection of alpha particles by a thin gold ofil predicted by Thomson's model much less, about the same or much greater than that predicted by Rutherford's atom model? (b) Is the probability of backward scattering (i.e., scattering of alpha particles at angles greater than 90^(@)) predicted by Thomson's model, much less, about the same, or much greater than that predicted by Rutherford's model? (c) Keeping other factors fixed, it is found experimentally,that for a small thickness t, the number of alpha particles scattered at moderate angles is propotional to t. What clues does this linear dependence on t provide? (d) In which atom model, is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of alpha particles by a thin ofil?
Answer» <html><body><p></p>Solution :(a) About the same. This is because we are talking of average <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of deflection. <br/> (b) Much less, because in Thomson's model, there is no such massive central core called the nucleusas in Rutherford's model. <br/> (c) This suggests that scattering is predominantly due to a single collision, because chance of a single collision increase with the <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of target atoms which increases linearly with the thickness of the ofil. <br/> (d) In Thomson model, positive charge is uniformaly <a href="https://interviewquestions.tuteehub.com/tag/distributed-956878" style="font-weight:bold;" target="_blank" title="Click to know more about DISTRIBUTED">DISTRIBUTED</a> in the spherical atom. Therefore, a single collision causes very little deflection. Therefore, average scattering angle can be explained only by considering multiple scattering. Thus it is <a href="https://interviewquestions.tuteehub.com/tag/wrong-1462035" style="font-weight:bold;" target="_blank" title="Click to know more about WRONG">WRONG</a> to ignore multiple scattering in Thomson's model. <br/>On the <a href="https://interviewquestions.tuteehub.com/tag/contrary-932525" style="font-weight:bold;" target="_blank" title="Click to know more about CONTRARY">CONTRARY</a>, in Rutherford's model, most of the scattering comes form a single collision. Therefore, multiple scattering may be ignored as a first approximation.</body></html>

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