Answer the homework 22

1.	Answer the homework 22
Answer» Homework 22:- (1) Sol:- Dimensions of cuboid = 10 × 0.8 × 0.16 (1dm = 0.1m) Volume of cuboid = lbh Volume of cuboid = 10 × 0.8 × 0.16m³ = 1.28m³ Hence, the volume of the cuboid is 1.28m³ (2) Sol:- Dimensions of cuboid = 15 × 10 × 8 Volume of the cuboid = lbh Volume of the cuboid = 15 × 10 × 8cm³ = 1200cm³ (3) Edge of cube = 8 cm. Volume of the Cube = (Edge)³ Volume of the Cube = (8)³ = 512cm³ Hence, the volume of the cube is 512cm³ (4) Sol:- Volume of the Box = 40 × (Edge)³ Edge of the cube = 3cm Volume of the box = 40 × 3³ = 1080cm³ (5) Sol:- Volume of 1 brick = 23 × 11 × 8cm³ Volume of Wall = 920 × 600 × 22cm³ No of bricks = Volume of Wall / Volume of 1 brick No of bricks = (920 × 600 × 22) / (23 × 11 × 8) = 600 × 2 × 5 = 6000 Hence, the no of bricks required is 6000

Answer»

Homework 22:-

(1)

Sol:- Dimensions of cuboid = 10 × 0.8 × 0.16 (1dm = 0.1m)

Volume of cuboid = lbh

Volume of cuboid = 10 × 0.8 × 0.16m³ = 1.28m³

Hence, the volume of the cuboid is 1.28m³

(2)

Sol:- Dimensions of cuboid = 15 × 10 × 8

Volume of the cuboid = lbh

Volume of the cuboid = 15 × 10 × 8cm³ = 1200cm³

(3) Edge of cube = 8 cm.

Volume of the Cube = (Edge)³

Volume of the Cube = (8)³ = 512cm³

Hence, the volume of the cube is 512cm³

(4)

Sol:- Volume of the Box = 40 × (Edge)³

Edge of the cube = 3cm

Volume of the box = 40 × 3³ = 1080cm³

(5)

Sol:- Volume of 1 brick = 23 × 11 × 8cm³

Volume of Wall = 920 × 600 × 22cm³

No of bricks = Volume of Wall / Volume of 1 brick

No of bricks = (920 × 600 × 22) / (23 × 11 × 8) = 600 × 2 × 5 = 6000

Hence, the no of bricks required is 6000

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