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of charges = 3So, NET electric POTENTIAL at the centre of tye equilateral triangle is = 3 × Vwhere, V = kq rHere, k = (1/4πε₀) q = q is given r = (√3)d/4Hence. Vₙₑₜ = 3 × (1/4πε₀)(q)/(√3d/4) = (1/4πε₀)(√3q/d)HOPE u liked my ANSWERPLS MARK me as brainliestThanks.



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