Antimony Sulphide (Sb_(2)S_(3)) reacts with sulphuric acid (H_(2)SO_(4)) to form Antimonic (H_(3)SbO_(4)) and sulphur dioxide (SO_(2)). What are the coefficients of H_(2)SO_(4),H_(3)SbO_(4),SO_(2) respectively in the balanced redox reaction.

Antimony Sulphide (Sb_(2)S_(3)) reacts with sulphuric acid (H_(2)SO_(4

1.	Antimony Sulphide (Sb_(2)S_(3)) reacts with sulphuric acid (H_(2)SO_(4)) to form Antimonic (H_(3)SbO_(4)) and sulphur dioxide (SO_(2)). What are the coefficients of H_(2)SO_(4),H_(3)SbO_(4),SO_(2) respectively in the balanced redox reaction.
Answer» `11,2,11` `2,4,4` `2,2,11` `11,2,14` Solution :REACTION : `Sb_(2)S_(3)+H_(2)SO_(4)toH_(3)SbO_(4)+SO_(2)` (i) Oxidation PART : (ii) Reduction part : Reduction `xx11:=11H_(2)SO_(4)to11SO_(2)" "...(R)` (III) REDOX : (O) + (R) = Redox `Sb_(2)S_(3)+11H_(2)SO_(4)to2H_(3)SbO_(4)+14SO_(2)` ... Redox (iv) Balancing O and H by `H_(2)O` : `Sb_(2)S_(3)+11H_(2)SO_(4)to2H_(3)SbO_(4)+14SO_(2)+8H_(2)O` (v) Coefficient of `H_(2)SO_(4)` = 11 Coefficient of `H_(3)SbO_(4)` = 2 Coefficient of `SO_(2)` = 14