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Aparticle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becmes 0.2 j, then the minimum and maximum values of .v. are |
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Answer» Solution :In case of perfectlycollision the velocity of COMBINED mass will be V/2 `thereforeKE= (1)/(2)(2m) ((v^(2))/(4))` `i.e.,(0.2)=(1)/(2)(0.2)((v^(2))/(4))rArrv=2sqrt(2)m//s` In case of perfectly elastic collision, FIRST particle stops and the second acquires the same velocity v `KE = (1)/(2)mv^(2)i.e, 0.2 (1)/(2)(0.1)v^(2)rArrv=2m//s` Therefore, minimum value of v is 2 m/s in case of perfectly elastic collision and maximum VALUEOF v is `2sqrt(2)` m/sin case of perfectly inelastic collision. |
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