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| 1. |
aq. solution of H2so4 is 30% by mass. find molality of solution and mole fraction of H2So4. |
| Answer» 30 g of H2so4 present in 100 g of solvent. ( mass of solvt.=100-30)Molality = wt. of solute ×1000/molecular wt. Of solute × wt. of solvent. = 30 ×1000/98 × 70 =1500/343 M=4.37...2 nd part, No.of moles of H2so4= 30/98=0.30 No.of moles of Water= 100/18=5.55Therefore, Mole fraction= 0.30/0.30+5.55 =0.30/5.85 =0.051.... Ans. | |