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aqueous solution of 6.3 g of oxadehydrate is made upto 250 ml. Thef 0.1 N NaOH required to coneutralize 10 ml of this solution is:An

Answer»

Equivalent mass of C2H2O4.2H2O = 126/2 = 63Normality of oxalic acid = 6.3/63 * 1000/250 = 0.4 NWe know that,N1V1= N2V2Where N1is normality of oxalic acidV1is volume of oxalic acidN2is normality of sodium hydroxideV2is volume of sodium hydroxideTherefore,0.4 * 10 = 0.1 * V2V2= 40 ml.Therefore 40 ml of NaOH is required to completely neutralize 10 ml of oxalic acid.



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