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ar (AABC)/ar(AQRP)=9/4 AB=18 cm and BC=15 cm, then find PR. |
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Answer» Ar(ABC)/ar(PQR)=K² K IS CONSTANT K=3/2 SINCE TRIANGLES ARE SIMILAR BC/PR=K PR=BC/KPR=15x2/3 PR=10 |
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