1.

Area lying between parabola y^(2)=4axand it's latuscrectum is

Answer»

`(4)/(3)a^(2)` sq unit
`(16)/(3)a^(2)` sq unit
`(8)/(3)a^(2)` sp unit
None of these

Solution :Required AREA `=2int_(0)^(a)sqrt(4ax)dx`
`=4sqrt(a)xx(2)/(3)[x^(3//2)]_(0)^(a)`
`=(8)/(3)a^(2)` sq unit


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