Area of a parallelogram, whose diagonals are 3^i+^j−2^k and ^i−3^j

1.	Area of a parallelogram, whose diagonals are 3^i+^j−2^k and ^i−3^j+4^k will be:
Answer» Area of a parallelogram, whose diagonals are $3^i +^j - 2^k a n d^i - 3^j + 4^k$ will be:

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Area of a parallelogram, whose diagonals are 3^i+^j−2^k and ^i−3^j+4^k will be:

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