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Area of region enclosed by the region y^2 le 3x , x^2+y^2 le 4 and y ge 0 is : |
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Answer» `(4pi-sqrt3)/6` `int_0^1 sqrt3sqrtxdxt int_1^2 sqrt(4-x^2)dx` `sqrt3(x^(3/2)/(3/2))^(1) +[ (xsqrt(4-x^2))/2 + 4/2 "sin"^(-1) x/2]_1^2` `(2SQRT3)/3 + 2 "sin"^(-1) 1-(1/2 sqrt3+ 2sin^(-1) 1/2)` `(2sqrt3)/3 + pi - sqrt3/2 -pi/3` `sqrt3(2/3-1/2 ) + (2pi)/3 rArr sqrt3/6 + (2pi)/3 =(4pi+sqrt3)/6` |
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