1.

arepfa 7.16A.i) BD-AC(iii) LABD=<BAC

Answer»

i)

In ΔABD & ΔBAC,AB = BA (Common)∠DAB = ∠CBA (Given)AD = BC (Given)

Hence, ΔABD ≅ ΔBAC.

( by SAS congruence rule).

(ii) Since, ΔABD ≅ ΔBACThen, BD = AC

(by CPCT)

(iv)Since, ΔABD ≅ ΔBACThen , ∠ABD = ∠BAC (by CPCT)



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