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Argon crystallizes in FCC arrangement and density of solid and liquid argon is 3/7 and 3gm/cc respectively. Find percentage of empty space in liquid Ar.A. 17B. 34C. 68D. 82 |
Answer» Correct Answer - B First method Let the volume of sloid Ar=100mL. Mass of solid Ar= `Vxxrho=100xx1.59gcm^(-3)=159g` Volume of liquid Ar= `("Mass")/(rho)=(159g)/(1.42gcm^(-3))=112mL` Since Ar crystallizes in fcc-type lattice, the packing fraction (PF)=0.74 Actual volume occupie by Ar=PF xx Volume of solid Ar=`0.74xx100=74mL` % Empty space in liquid Ar= `((112-74))/(112)=33.92%` |
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