1.

अरहिटप्र 'बसबर 2s2Q =4 तब sec O + cosec® ST Xs17. यदि 7sin g जेल 43A 2., ®L l ®F\/_.3——- s el -

Answer»

Let theta = A7 sin²A + 3 cos²A = 4=> 3 sin²A + 3 cos²A + 4 sin²A = 4=> 3 ( sin²A + cos²A ) + 4 sin²A = 4 => 3 + 4 sin²A = 4 => 4 sin²A = 1 => sin²A = 1/4=> sin A = 1/2 => sin A = sin 30°=> A = 30° .

Then, sec 30 + cosec 30= 2/sqrt (3) + 2


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