Arjun and Karna had an archery competition where they had to shoot a t

1.	Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with the centermost circle having a score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation of the score of the innermost circle so as to decide who the winner is assuming the winner is less deviated from the bulls eye. Points87654321Arjun(fi)571423111043karana(fi)58112414853
Answer» Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with the centermost circle having a score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation of the score of the innermost circle so as to decide who the winner is assuming the winner is less deviated from the bulls eye. $\begin{matrix} P o i n t s & 8 & 7 & 6 & 5 & 4 & 3 & 2 & 1 A r j u n (f_{i}) & 5 & 7 & 14 & 23 & 11 & 10 & 4 & 3 k a r a n a (f_{i}) & 5 & 8 & 11 & 24 & 14 & 8 & 5 & 3 \end{matrix}$

Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with the centermost circle having a score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation of the score of the innermost circle so as to decide who the winner is assuming the winner is less deviated from the bulls eye. Points87654321Arjun(fi)571423111043karana(fi)58112414853

Answer»

Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with the centermost circle having a score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation of the score of the innermost circle so as to decide who the winner is assuming the winner is less deviated from the bulls eye.

$\begin{matrix} P o i n t s & 8 & 7 & 6 & 5 & 4 & 3 & 2 & 1 A r j u n (f_{i}) & 5 & 7 & 14 & 23 & 11 & 10 & 4 & 3 k a r a n a (f_{i}) & 5 & 8 & 11 & 24 & 14 & 8 & 5 & 3 \end{matrix}$

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