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Around a point charge of `1 nC`, what is the distance of an equipotential surface of `0.9V` ? |
Answer» Here `q = 1nC = 10^(-9) C, V = 0.9 V, r = ?` As `V = (q)/(4pi in_(0) r)` `:.r = (q)/(4pi in_(0) r) = (10^(-9)xx9xx10^(9))/(0.9) = 10m` |
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