Arrabge in decreasing order, the energy of 2s orbital in the following

1.	Arrabge in decreasing order, the energy of 2s orbital in the following atoms H, Li, Na, K
Answer» `E_(2s) (H) GT E_(2s) (Li) gt E_(2s) (Na) gt E_(2s) (K)` `E_(2s) (H) gt E_(2s) (Na) gt E_(2s) (Li) gt E_(2s) (K)` `E_(2s) (H) gt E_(2s) (Na) = E_(2s) (K) gt E_(2s) (Li)` `E_(2s) (K) gt E_(2s) (Na) gt E_(2s) (Li) gt E_(2s) (H)` Solution :CORRECT decreasing order is (a). This is because as atomic number (nuclear charge) increases, all the ORBITALS are PULLED closer to the nucleus. Closer is an orbital to the nucleus, less is its energy

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