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Arrange A,BC D,E and H in order of increasing electrode potential in the electrochemical series if A+H_(2)SO_(4)rarrASO_(4)+H_(2),ACI_(2)+C rarr CCI_(2)+A ECI_(2)+C rarr NO reaction , 2 BCI+ DrarrDCI_(2)+2 B H_(2)SO_(4)+D rarr NO reaction |
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Answer» Solution :(i) Since `H_(2)SO_(4)` reacts with A to evolve `H_(2)` but not with D therefore `E^(@)` of A is lower than that of H while than of D is higher than that of H i.e D lis above H while A lies below H in the electrochemical series (ii) since D displaces B from BCI therefore `E^(@)` of D is lower than that of B From (i),(ii) and (III) it followis that the overall order of decreasing electrode potential is `BgtDgtH gtAgtCgtE` conversely `E^(@)` INCREASES in the order : `Elt Clt A lt H lt D lt B` |
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