Arrange in increasingorderof energy (I ) n=2,l =0,m_(1)= 0 m_(s ) = (1)/(2) (ii) n= 2 , l= 1 , m_(1) =+ 1 , m_(s )= (1)/(2) (ii)n=3 ,l m_(1) =+ 1 ,m_(s) = (1)/(2) (iv)n=3,l= m_(l)=-1 m_(s )=+ (1)/(2)

Arrange in increasingorderof energy (I ) n=2,l =0,m_(1)= 0 m_(s ) = (

1.	Arrange in increasingorderof energy (I ) n=2,l =0,m_(1)= 0 m_(s ) = (1)/(2) (ii) n= 2 , l= 1 , m_(1) =+ 1 , m_(s )= (1)/(2) (ii)n=3 ,l m_(1) =+ 1 ,m_(s) = (1)/(2) (iv)n=3,l= m_(l)=-1 m_(s )=+ (1)/(2)
Answer» SOLUTION :(i) n=2 and l=1 : 2P (II) n=2 andl=1 : 2p (iii)n=3and l=2 : 3D (iv) n=3 andl=1 : 3p Increasingorderof energy: 2S ,2p,3p ,3d increasingorderof energy(i) ,(ii) ,(iv) ,(iii)