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Arrange Na^(+),Mg^(2+) and Al^(3+) in the increasing order of ionic radii.Give reason. |
Answer» Solution :`NA^(+),Mg^(2+)` and `Al^(3+)` are isoelectronic cations. The CATION with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus. HENCE the increasing order of ionic radii is, `r_(Na^(+))gtr_(Mg^(2+))gtr_(Al^(3+))` |
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