Arrange the following alkyl halides in decreasing order of the rate of beta-elimination reaction with alcoholic KOH (A)CH_3-undersetunderset(CH_3)|oversetoversetH|C-CH_2Br (B)CH_3-CH_2-Br (C )CH_3-CH_2 -CH_2-Br

Arrange the following alkyl halides in decreasing order of the rate of

1.	Arrange the following alkyl halides in decreasing order of the rate of beta-elimination reaction with alcoholic KOH (A)CH_3-undersetunderset(CH_3)\|oversetoversetH\|C-CH_2Br (B)CH_3-CH_2-Br (C )CH_3-CH_2 -CH_2-Br
Answer» A gt Bgt C C gt B gt A B gt C gt A A gt C gtB Solution :More the number of `beta`-substituents, more stable alkene it will give on `beta`-elimination. SINCE (A) has TWO,(C ) has one `beta`-METHYL substituent while (B) have no `beta`-methyl substituent, therefore, reactivity towards `beta`-elimination decreases in the ORDER : A gt C gt B