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Arrange the following carbanions in decreasing order of stability: `underset((I))(.^(Theta)(CH_(2))-Cl)` , `underset((II))(.^(Theta)(CH_(2))-CN)`, `underset((III))(.^(Theta)(CH_(2))-NO_(2))`, `underset((IV))(.^(Theta)CH_(2)-CH_(3))`A. `IIIgtIIgtIVgtI`B. `IIIgtIIgtIgtIV`C. `IIIgtIgtIIgtIV`D. `IIgtIIIgtIgtIV` |
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Answer» Correct Answer - B Due to `-M` and `-I` of group. |
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