1.

Arrange the following carbanions in order of their decreasing stability. (I) H_(3)C-C-=C^(-) (II) H-C-=C^(-) (III) H_(3)C-CH_(2)^(-)

Answer»

IgtIIgtIII
IIgtIgtIII
IIIgtIIgtI
IIIgtIgtII

Solution :The order of decreasing stability of carbons is:
`underset((I))(H-C-=C^(-)) gt underset((I))(CH_(3)-C-=C^(-)) gt underset((III))(CH_(3)-CH_(2)^(-))`
sp-hybridised carbon ATOM is more electronegative than `sp^(3)`-hybridised carbon atom annd hence, can accomodate the negative charge more effectively. `-CH_(3)` group has +I effect, therefore, it intensifies the negative charge and hence, destabilises the carbanion .


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