Arrange the following compounds in increasing order of `S_(N^(1))` reactivity. (a). (I). `ClCH_(2)CH=CHCH_(2)CH_(3)`, (II). `CH_(3)C(Cl)=CHCH_(2)CH_(3)`, (III). `CH_(3)CH=CHCH_(2)CH_(2)Cl` (b). (I). `CH_(3)CH_(2)Br`, (II). `CH_(2)=CHCH(Br)CH_(3)`, (III). `CH_(2)=CHBr,` (IV). `CH_(3)CH(Br)CH_(3)` (c). (I). `(CH_(3))_(3)CBr`, (II). `(CH_(3))_(2)CHBr`, (III). `CH_(3)CH_(2)CH_(2)Br`,

Arrange the following compounds in increasing order of `S_(N^(1))` rea

1.	Arrange the following compounds in increasing order of `S_(N^(1))` reactivity. (a). (I). `ClCH_(2)CH=CHCH_(2)CH_(3)`, (II). `CH_(3)C(Cl)=CHCH_(2)CH_(3)`, (III). `CH_(3)CH=CHCH_(2)CH_(2)Cl` (b). (I). `CH_(3)CH_(2)Br`, (II). `CH_(2)=CHCH(Br)CH_(3)`, (III). `CH_(2)=CHBr,` (IV). `CH_(3)CH(Br)CH_(3)` (c). (I). `(CH_(3))_(3)CBr`, (II). `(CH_(3))_(2)CHBr`, (III). `CH_(3)CH_(2)CH_(2)Br`,
Answer» The order of reactivyt of alkyl halies towards `S_(N^(1))` reactions is: Allylic gt Tertiary gt Secondary gt primary gt Vinylic Based on this, the increasing order of reactivity in different alkyl halides listed above is: (a) (II) `lt(III)lt(I)` (b). `(III)lt(I)lt(IV)lt(II)` (c). `(III) lt (II) lt (I)`.

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