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Arrange the following in increasing order of pH. KNO_(3(aq)) , CH_3COONa_((aq)), NH_4Cl_((aq)) , C_6H_5COONH_(4(aq)) |
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Answer» Solution :(i)`KNO_3` is a salt of STRONG acid `(HNO_3)` strong base (KOH), thus its aqueous solution is neutral, pH = 7. (ii)`CH_3COONa` is a salt of weak acid `(CH_3COOH)` and strong base (NaOH), thus, its aqueous solution is basic, pH `gt` 7. (iii)`NH_4Cl` is a salt of strong acid (HCL) and weak base (`NH_4OH`) thus, its aqueous solution is ACIDIC, pH `lt` 7. (iv)`C_6H_5COONH_4` is a salt of weak acid, `C_6H_5COOH` and weak base, `NH_4OH`. But `NH_4OH` is slightly STRONGER than `C_6H_5COOH`. thus, pH is slightly `gt` 7. Therefore, increasing order of pH of the GIVEN salts is, `NH_4Cl lt C_6H_5COONH_4 gt KNO_3 lt CH_3COONa` |
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