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Arrange the following in order of decreasing bond angle ,giving reason :NO_(2), NO_(2)^(+), NO _(2)^(-) |
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Answer» Solution :`NO_(2)^(+)gt NO_(2)gtNO _(2)^(-)` . This is because ` NO_(2)^(+)` has no lone pair of elecrtons (i.e. has only BOND pairs on TWO Sides ) and hence it is linear . ` NO_(2)`has one unshared electon while` NO_(2)^(-)`has one unsharedelectron pair . There are greateron N-O bonds CASE of ` NO_(2)^(-)` than in case of ` NO_(2)`.
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