Arrange the following in order of (i) increasing N-O bond length (ii) increasing bond angles NO_(2)^(+) , NO_(2)^(-) , NO_(3)^(-) Give reasons .

Arrange the following in order of (i) increasing N-O bond length (ii)

1.	Arrange the following in order of (i) increasing N-O bond length (ii) increasing bond angles NO_(2)^(+) , NO_(2)^(-) , NO_(3)^(-) Give reasons .
Answer» Solution :Applying rules for finding the TYPE of hybridisation of central atom, N atom in `NO_(2)^(+)` is `sp` hybridised while in `NO_(2)^(-) and NO_(3)^(-) ` , it is`sp^(2)`hybridised . Their structures are `{:("BOND angle ":180^(@) ,132^(@), 120^(@)),("Bond order ":2, (2+1)/(2) = 1.5 , (2+1+1)/(3) = (4)/(3) = 1.33):}` Bond lengths :` NO_(2) ^(+) LT NO_(2)^(-) lt NO_(3)^(-)`