InterviewSolution
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InterviewSolution
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Arrange the following in the order of increasing mass (at. Mass of O=16, Cu=63, N=14) (I) one atom of oxygen (II) one atom of nitrogen (III) `1xx10^(-10)` mole of oxygen (IV) `1xx10^(-10)` mole of copperA. `II lt I lt III lt IV`B. `I lt II lt III lt IV`C. `III lt II lt IV lt I`D. `IV lt II lt III lt I` |
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Answer» Correct Answer - A Mass of one atom of oxygen `=16/(6.023xx10^(23))=2.66xx10^(-23)` Mass of one atom of nitrogen `=14/(6.023xx10^(23))=2.32xx10^(-23)` Mass of `1xx10^(-10)` mole of oxygen `=16xx10^(-10)` Mass of `1xx10^(-10)` mole of copper `=63xx1xx10^(-10)` `=63xx10^(-10)` So, the order of increasing mass is `II lt I lt III lt IV`. |
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