Arrange the following metals in order of their increasing reducing power. K+ /K = - 2.93 V, Ag+ /Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = - 2.37 V Cr3+/Cr = - 0.74 V.

Arrange the following metals in order of their increasing reducing pow

1.	Arrange the following metals in order of their increasing reducing power. K+ /K = - 2.93 V, Ag+ /Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = - 2.37 V Cr3+/Cr = - 0.74 V.
Answer» Lower the reduction potential, easily if gets oxidized hence greater is the reducing power, therefore the increasing order of reducing power is Ag < Hg < Cr < mg < K.

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Arrange the following metals in order of their increasing reducing power. K+ /K = - 2.93 V, Ag+ /Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = - 2.37 V Cr3+/Cr = - 0.74 V.

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