1.

Arrange the following molecules in increasing order of intermolecular forces : C_(2)H_(6),CH_(3)NH_(2),CH_(3)F and CH_(2)F_(2)

Answer»

Solution :GREATER the intermolecular forces, greater is the boiling point.
`C_(2)H_(6)` has only London forces,`CH_(3)NH_(2)` has hydrogen BONDING and London forces. `CH_(3)F` and `CH_(2)F_(2)` have dipole-dipole attractions besides London forces, but dipole-dipole attractions in `CH_(2)F_(2)` are greater than those in `CH_(3)F`. Hence, ORDER of boiling point is `C_(2)H_(6)(-88^(@)C)ltCH_(3)F(-78^(@)C)ltCH_(2)F_(2)(-52^(@)C)ltCH_(3)NH_(2)(-6^(@C)`.


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