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Arrange the given dicarbon species in order of their bond lengths giving reasons L C_(2), C_(2)^(-), C_(2)^(2-) . |
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Answer» Solution :Total number of electrons in `C_(2) = 12` Its electronic configuration is `sigma _(1s)^(2) sigma _(1s)^(**2) sigma _(2s)^(2) sigma _(2s)^(**2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)`"" BOND order = `(1)/(2) (8-4) = 2` E.C. of `C_(2)^(-)=sigma _(1s)^(2) sigma _(1s)^(**2) sigma _(2s)^(2) sigma _(2s)^(**2) pi_(2p_(x))^(2)pi_(2p_(y))^(2) sigma _(2p_(z))^(1)`"" Bond order `= (1)/(2) (9-4) = 2.5` E.C. of `C_(2)^(2-) = sigma _(1s)^(2) sigma _(1s)^(**2) sigma _(2s)^(2) sigma _(2s)^(**2) pi_(2p_(x))^(2)pi_(2p_(y))^(2) sigma _(2p_(z))^(2)`"" Bond order ` = (1)/(2) (10 -4)=3.0` As GREATER the bond order ,SHORTER is the bond LENGTH , therefore , order of bond length will be `C_(2)^(2-) lt C_(2)^(-) lt C_(2)` . |
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