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Arrange the ions F^(-),O^(2-) and N^(3-) in the increasing order of their ionic radii. Give reason |
Answer» Solution :`F^(-),O^(3-)` and `N^(3-)` are isoelectronic species. The anion with the greater negative charge will have a LARGER radius because of the lesser ATTRACTION of the ELECTRONS to the NUCLEUS. Hence the increasing order of ionic radii is, `r_(N^(3-))gtr_(O^(2-))gtr_(F^(-))` |
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